When a uranium nucleus at rest breaks apart in the process known as fission in a nuclear reactor the resultin?

Webb

When a uranium nucleus at rest breaks apart in the process known as fission in a nuclear reactor, the resulting fragments have a absolute kinetic vigour of about 205 MeV. How highly mass was lost broach the process?



Hamilton Branch

assuming from your question that all of the loss of mass was converted to KE of the fission fragements, one atomic mass unit (amu) equals 931.46 Mevso...... 205MeV/931.46MeV/amu = 0.220084598 amu1 amu = 1.66E-27Kg so 1.66E-27Kg/amu * 0.220084598 amu = 3.65459E-28Kgusually, the KE of the fission fragments accounts for 85% of the total energy released in fission of U235



Carbon Hill

kinetic energy of the resulting fragments is 205 Mev which is previously stored in the nucleus as a potential energy because of the force between proton-proton because of their electric charge and force between proton-proton, proton-neutron, neutron-neutron because of their quarks structure before fission occurs...and when it occurs then the energy produces due to lose of mass....So, as an equation of Einstein..E=m. c